Hi
I am trying for providing navigation for records like the way provided int the following examle.
http://www.w3schools.com/xml/tryit.asp?filename=cd_navigate but my xml file is not in the standard format. It looks like
<FormData>
<Form name="ADDRCHG" description="Address Change Form">
<Element name="FirstName" value="S">
</Element>
<Element name="LastName" value="B">
</Element>
<Element name="NewAddressLine1" value="1234 some street">
</Element>
</Form>
<Form name="ContactUsNPF" description="Contact US Form for NPF">
<Element name="FirstName" value="S">
</Element>
<Element name="LastName" value="B">
</Element>
<Element name="Question" value="Hey, how do I use your site?">
</Element>
</Form>
<Form name="ContactUsBTF" description="Contact US Form for BTF">
<Element name="FirstName" value="S">
</Element>
<Element name="LastName" value="B">
</Element>
</Form>
</FormData>
i used XSL to display the records in HTML format and everything works fine. my XSL looks like
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl">
<xsl:template match="/">
<html>
<body>
<h1>Forms Details:</h1>
<table border="0" cellpadding="2">
<xsl:for-each select="FormData/Form">
<tr>
<th>
<xsl:value-of select="@description"/>
</th>
</tr>
<tr>
<xsl:for-each select="Element">
<tr>
<td> <xsl:value-of select="@name" />:
<xsl:value-of select="@value" /> </td>
</tr>
</xsl:for-each>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
with this one i am able to display the entire data in a single page. But i want to place buttons at the bottom of XSL file and provide navaigation like MovePrevious, MoveNext, with one record in each page. As my XML is not in the standard format i couldn't use the code provided in the example. Could someone please help me.
Thanks in advance.
[ November 18, 2004: Message edited by: Mamta Katamnent ]
