static instance of Generic class

[Amirr Rafique]

As per below lines from Ivor Hoton's book

Even though all types produced from a given generic type share the same run-time type, they still
have their own independent static fields. For example, suppose you were to add a static field�
count, say� of type int to the LinkedList<> type definition to record the number of objects created.
You�d then add a statement to the constructor to increment count each time it was called. Each
type instance, such as LinkedList<String> or LinkedList<Point>, would have its own copy of count,
so the static count member of the LinkedList<String> type would correctly reflect the number of
times the LinkedList<String> constructor had been called.

Please explain

 class Type2<T>{
static int count;
 
public Type2(){
count ++;
}
 
public int getCount(){
return count;
}
}
 
public class  TypeTest
{
public static void main(String[] args) 
{
 
Type2<String> type2 = new Type2<String>();
System.out.println("Count of Generic is - " + type2.getCount());
 
Type2<String> t2 = new Type2<String>();
System.out.println("Count of Generic is - " + t2.getCount());
 
Type2<Integer> t3 = new Type2<Integer>();
System.out.println("Count of Generic Integer is - " + t3.getCount()); //Why this line print 3
}
 
}
 
   

Thanks

[Garrett Rowe]

Regarding information you find in various sources, in the words of Ronald Reagan Trust, but verify.
[ May 31, 2006: Message edited by: Garrett Rowe ]

[Amirr Rafique]

Please see my verifying program. It doesn't seems working according to statemet.

[wise owen]

You used "static int count" which is class variable. There is only one for Type2<T> class.