Originally posted by Henry Wong:
This question has appeared on this forum before -- just use the search link above to look for either "SSBool" or "dokey".
Basically... the key to getting the answer is an understanding that the bitwise AND operator has a higher precedence than the bitwise OR operator.
Henry
[ September 20, 2006: Message edited by: Henry Wong ]
Simplest answer is it is all in operator precedence!