Barry Gaunt posted
"default" (as a word) is not an access qualifier. What is known as "default access" (that is package access) is specified by supplying no access modifier at all.
The question itself is ambiguous, you'd better forget it.
"default" as a word is of course not a modifier. But when I follow the makers of this
test like a computer, I would say that f is false the same way, because:
wouldn't compile either
Bu.