zip files without path info...

[Eric Martin]

I don't know if this is the best board for the question, but I am trying to do this from a servlet, so...

I am using ZipOutputStream to create zip file containing 3 files on our server. I don't want to files to be inside directories when they are zipped, so how do I add them without the path information?

// Add files to a zip and send to user
// These are the files to include in the ZIP file
String[] filenames = new String[] {repeatTemp, template, mergeTemp};
 
// Create a buffer for reading the files
byte[] buf = new byte[1024];
 
// res.setContentType("application/x-download");
res.setContentType("application/zip");
res.setHeader("Content-Disposition", "attachment; filename="
    + zipFileName);
ZipOutputStream zos = new ZipOutputStream(res.getOutputStream());
for (int i = 0; i < filenames.length; i++) {
    FileInputStream in = new FileInputStream(filenames[i]);
 
    // Add ZIP entry to output stream.
    zos.putNextEntry(new ZipEntry(filenames[i]));
 
    // Transfer bytes from the file to the ZIP file
    int len;
    while ((len = in.read(buf)) > 0) {
        zos.write(buf, 0, len);
    }
 
    // Complete the entry
    in.close();
    zos.closeEntry();
}
zos.finish();
res.flushBuffer();

The 3 filenames all include the full server path to the file and they are getting added to the archive inside a directory structure that matches the server path.

TIA.

[Bear Bibeault]

Moved to the I/O forum.

[Rajagopal Manohar]

just guessing

try changing

// Add ZIP entry to output stream.
zos.putNextEntry(new ZipEntry(filenames[i]));

to

 zos.putNextEntry(new ZipEntry(new File(filenames[i]).getName())); 

[Eric Martin]

Thanks! I was able to get it working with the following changes:

int slash;
String name;
for (int i = 0; i < filenames.length; i++) {
    FileInputStream in = new FileInputStream(filenames[i]);
 
    // Add ZIP entry to output stream.
    if (filenames[i].lastIndexOf('\\') != -1) {
        slash = filenames[i].lastIndexOf('\\');
    } else {
        slash = filenames[i].lastIndexOf('/');
    }
    name = filenames[i].substring(slash + 1);
    zos.putNextEntry(new ZipEntry(name));
 
    // Transfer bytes from the file to the ZIP file
    int len;
    while ((len = in.read(buf)) > 0) {
        zos.write(buf, 0, len);
    }
 
    // Complete the entry
    in.close();
    zos.closeEntry();
}

The ZipEntry is what controls how it is represented in the zip file.

-Eric
[ December 13, 2005: Message edited by: Eric Martin ]