lastIndexOf() Question

[Sam Bluesman]

If i have an array of integers called, say, integerArray[], and i am looking for the last location that contains, say, 1, then how do i use the lastIndexOf() method, as it does not seem to work when i try it.

my code is similar to:

 
    int lastAddress = integerArray.lastIndexOf(1);
    System.out.println(lastAddress);
 

Thanks
[ November 13, 2005: Message edited by: Sam Bluesman ]

[Rob Spoor]

Arrays don't have methods and have only 1 field, length.
java.util.Arrays has some utility methods for arrays, but no lastIndexOf, so you'll have to write your own utility class that implements it. Just traverse the array backwards, starting at intArray.length - 1.

[Ilja Preuss]

Or use the ArrayUtils class from http://jakarta.apache.org/commons/lang/

[Ernest Friedman-Hill]

Originally posted by Rob Spoor:
Arrays don't have methods

Actually they have all the methods of the class java.lang.Object: equals(), hashCode(), wait(), notify(), notifyAll(), toString(), finalize(), getClass(), and clone() (which is public in all array classes.)

[Rob Spoor]

Right, stupid of me. Since arrays are Objects of course they have these...

[Campbell Ritchie]

Is lastIndexOf() in the ArrayList class, maybe?

[Rob Spoor]

In all Lists.