SAXParseException

Greenhorn

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posted 15 years ago

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Hi there this is my code:

<jsp:root xmlns:jsp="http://java.sun.com/JSP/Page" version="2.0">
<jsp:directive.page contentType="text/html; charset=UTF-8" />
<jsp:output doctype-root-element="html"
doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
doctype-system="http://www.w3c.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">

some html code....

</html>
</jsp:root>

I still got the exception :org.xml.sax.SAXParseException: The markup in the document following the root element must be well-formed. Doeas anyone know why?

William Brogden

Author and all-around good cowpoke

Posts: 13078

posted 15 years ago

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There are methods in SAXParseException to get the line and column number that the parser objects to.

Bill

Milan Vasic

Greenhorn

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posted 15 years ago

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Tnx Bill.

vaske

Milan Vasic

Greenhorn

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posted 15 years ago

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I try to validate my jsp with a loot of on line validators, and my jsp is well formated, but when I try to parse that file with parse method on documentbuilder object I got this error.

William Brogden

Author and all-around good cowpoke

Posts: 13078

posted 15 years ago

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Have you been able to extract the line and column from the exception?
How is the jsp source code being generated?

Bill

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