q 25 from tipsmart.com

[jake noi]

From TipSmart's sample paper
class MyClass
{
public static void main(String []args)
{
final int i = 100;
byte b = i;
System.out.println(b);
}
}
Here is the answer from website => Will compile and print 100
How come that we don't need to explicitly cast from int to byte?
Thank you for your clarification

[Michael Burke]

Because the int is final and so is a constant. The compiler can figure out the value at compile time and since 100 fits into a byte the compiler allows it. Anyone else want to clarify?

[Vladimir Kositsky]

My compiler issued approval
It does not compile without final