casting

[Lori Zink]

Given these declarations:
int i = 5;
short s = 3;
char c = 'a';
byte b = 2;
The following stuff compiles and I don't know why...
s += i;
c += i;
b += i;
The following stuff does NOT compile (needs explicit cast) and I don't understand WHY NOT if the first stuff did!
s = s + i;
c = c + i;
b = b + i;

------------------

[Namrata Shetty]

int i = 5;
short s = 3;
char c = 'a';
byte b = 2;
The following stuff compiles and I don't know why...
s += i;
c += i;
b += i;
the way the above above works is
s+=i; is actually seen by JVM as s=(short)(s+i);
casting is done by JVM whereas
s=s+i; //it needs an explicit cast
similarly for the other cases

[Rashmi Hosalli]

Thats because when you use the operation and the assignment at the same time i.e += there is an implicait cast included...hence
s+=i is equivalent to s = (short)s+i;
but when you say s = s + i,there is no casting done and you get a compile time error.
Rashmi

[Alex Sbityakov]

BTW,
++,-- have implicit casts too,
Alex

[Guoqiao Sun]

Hi, all, as far as I know, the following operator will carry out implicit cast:

+=
-=
*=
/=
%=
<<=
>>=
>>>=
&=
^=
|=

Correct me if i am wrong,
guoqiao

Originally posted by Alex Sbityakov:
BTW,
++,-- have implicit casts too,
Alex

[Mini Pilla]

I don' think ++,-- have implicit cast.
Thanx
Rajani

Originally posted by Alex Sbityakov:
BTW,
++,-- have implicit casts too,
Alex