Originally posted by Val Lee:
From the JLS,�8.8.7 Default Constructor
So I think it is false.
Huh?
That statement says that a compiler error occurs if the superclass doesn't have an accessible no-args constructor. This would only be an error is the default constructor tried to invoke the no-args constructor.
Therefore, this statement is proving the fact that a default constructor invokes the no-args constructor of the superclass, not the other way around.
Try this:
Corey