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why there are no compile errors of these codes?

public class Outter{
private final int i = 10;
byte k = i; //I thought here should be: byte k = (int)i;
}
 
jaman tai
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Sorry, typing error.
i think "byte k = i;" should be "byte k = (byte)i;"
 
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That's because "10" is a compile-time constant, assigned to a final var i, which becomes also a compile-time constant.

So, in this case, writing :
byte b = i;
is equivalent to :
byte b = 10;

(Compiler knows that 10 is in byte range, so does not complain.)
[ October 12, 2005: Message edited by: Seb Mathe ]
 
jaman tai
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oh, good answer. thanx
 
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yes jaman since its is a compile time constant...
u can write byte b=i...until i is a compile time constant..

thanks
sri
 
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