reg expression

[sundar sankar]

Hi all,
In the below pro iam getting output as 1,2 but i except 1,2,12,25 since mextInt will move the pointer to next int value.please help me in this regard
thanks in advance
sankar

import java.util.*;
import java.io.*;
class reg4
{
static long aLong;
public static void main(String ava[])
{
try{
Scanner sc = new Scanner("1 2asa 12,25");
//assert(sc.hasNextInt()):"nega value"+sc.hasNextInt();
do{
//aLong += sc.nextInt();
System.out.println(sc.nextInt());
}while(sc.hasNextInt());
}catch(Exception e){e.printStackTrace();}//System.out.println(aLong);
}}

[Chandra Bhatt]

Hi Sankar,

If you put your code inside the "

" tag, it would look
more better and readable. It may attract greedy ranch fellows to answer your
post.


Thanks,

[Henry Wong]

In the below pro iam getting output as 1,2 but i except 1,2,12,25 since mextInt will move the pointer to next int value.please help me in this regard

The nextInt() method does not "move the pointer to the next int value". It tries to interpreted the next token as an int value. The hasNextInit() method doesn't try to find if there are more ints in the string, it returns whether the next token can be interpreted as an int.

Anyway, if you only want ints, one way to fix this is to make everything that is not a digit, a delimiter. Like so...

sc.useDelimiter("\\D+");

Henry

[nitin pokhriyal]

Apart from that the output will be 1 as henry already said "The hasNextInit() method doesn't try to find if there are more ints in the string, it returns whether the next token can be interpreted as an int."
[ June 26, 2007: Message edited by: nitin pokhriyal ]
[ June 26, 2007: Message edited by: nitin pokhriyal ]