Memory allcocation at time of loading class..

[kaushik vira]

HI, friends..

i am not getting how actual memory allocation is take place at time of loading a class..

how staic block is executed....

as we have thought that in java we can`t use any variable before initialization then here why System.out.println(staticBlock.i); is printing value 0...


public class staticBlock {


int j =9;
static{
System.out.println(staticBlock.i);
}

static int i =10;

public static void main(String args[])
{
System.out.println(staticBlock.i);
}

}

[Manfred Klug]

Originally posted by kaushik vira:
as we have thought that in java we can`t use any variable before initialization then here why System.out.println(staticBlock.i); is printing value 0...

Since the compiler doesn't try to find all occurences where you use a variable before it's initialized. Another example that compiles:

public class Test {
    static{
        System.out.println(getI());
    }
 
    public static int getI() {
        return i;
    }
 
    static int i =10;
 
    public static void main(String args[]) {
        System.out.println(getI());
    }
}

[Deepak Jain]

Well! Declaring static variable i after the static initialization block throws me a Compiler error: "Cannot reference a field before it is defined"

However if i declared "i" before static initialization block , It compiles and gives a result 10. [The value assigned to the variable]

Is this expected and correct?
Does the order of declaration matters when it comes to declaring members of class, I thought java uses forward refrencing.
I have 1.5 compiler.
Thanks
Deepak

[Manfred Klug]

Hi Deepak,

have a look at Forward Referencing

[madhu v pe]

Kaushik,

static variables will get initialized to 0 by default.

Thanks