taking first four numbers from a set of number

[preethi Ayyappan]

Hi,
I need to get first four number from 14 numbers .I can able to get last 4 numbers using substring.But i am unable to get first four numbers.anyone please assist me to do this.

Thanks.

[Kuladip Yadav]

You can use for loop from that
Increment index 0 to 3 and get number at that position.

Thanks

[Paul Sturrock]

You don't need to use a loop. Assuming the "number" is infact a String (which I'm infering by preethi Ayyappan saying they can get the last 4 digits with substring); the String class has a substring method that takes a begin and end index. Just use that.

[Amit Ghorpade]

I can able to get last 4 numbers using substring

You mean to say that the set is a String?
If yes then what is the problem in getting first four characters

Paul beat me on that by a minute
[ August 13, 2008: Message edited by: Amit Ghorpade ]

[preethi Ayyappan]

Thanks.
I have used substring to get last 4 numbers like the following:

    
String callerid="1234567890";
int call=callerid.length();
 String newcallerid;
  newcallerid=(callerid.substring(call-4,call));
 

the output will be 7890.But i am unable to get first 4 numbers.please assist me in code how can we use the same substring for this too.
[ August 13, 2008: Message edited by: preethi Ayyappan ]

[Kamal Mettananda]

Just use the following method in String class.

String substring(beginIndex, endIndex);

[Stephen Davies]

public class Subber {
 
String theString = "1234567891011121314";

public String getFirstFour(){

/**don't forget, substring method doesn't change 
*the original string, so we must make a variable 
*to hold the copy*/

String firstFour = theString.substring(0,4);

/**I believe the index parameters for the substring method
 * Work on the number of characters in a string not the index, 
 * so 0,3 would only return 123, hence 0,4 to return 1234
 */

return firstFour;

}


public static void main(String[] args) {

Subber sub = new Subber();
System.out.println(sub.getFirstFour());
 


 
}
 
}

[preethi Ayyappan]

I have written the following code:

  
public static void main(String[] args){
  String callerid ="CD12345678";
  int call=callerid.length();
  int beginIndex='c';
  int endIndex='3';
  String newcallerid;
  newcallerid=(callerid.substring(beginIndex,endIndex));
 
 System.out.print(newcallerid);
    //System.out.println(newcallerid);
    
   
 
  }
  

I am getting the following error:

Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: 49
at java.lang.String.substring(String.java:1935)
at CurrentTime.main(CurrentTime.java:13)

[preethi Ayyappan]

thank you so much.

[Rob Spoor]

That's because you're using characters as your indexes. These will be converted to their ASCII values.

[Kamal Mettananda]

int beginIndex='c';
int endIndex='3';

I guess this is a mistake. You have used character 'c' instead of 0. Shouldn't it be;
int beginIndex = 0;
[ August 13, 2008: Message edited by: Kamal Mettananda ]