How to get rid of this exception?

[sue ti]

I am trying to parse the following xml
<?xml version="1.0" encoding="UTF-8" ?>
<Root>
< Global >
< Token >R< /Token>
< Force>0</Force>
</ Global>
< ServiceSettings>
< Service>
< ServiceName>A<ServiceName>
<TokenType>S</TokenType>
< Login>0</Login>
< Transaction>1</Transaction>
</ Service>
< Service>
< ServiceName>B<ServiceName>
<TokenType>RSA</TokenType>
< Login></Login>
< Transaction>0</Transaction>
</ Service>
</ ServiceSettings>
</Root>


Iam using following piece of java code to parse the above xml which I am getting from server in the form of MutableString(strConfigXML).

private Document m_document;
DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();
String strSrc = strConfigXML.toString();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(strSrc));
m_document = builder.parse(is);


Its giving the exception as
org.xml.sax.SAXParseException: The content beginning "< " is not legal markup. Perhaps the " " () character should be a letter.


Can anyone please guide me as I am new to Java and Xml as well?

[William Brogden]

Obviously, the input text is not what the parser expects at some point. This is a pretty common problem - something as simple as a leading space in front of the <?xml or a control code that is not legal UNICODE.

You can catch the SAXParseException and extract the line and column where the error occurred.

Bill