wide-vararg VS box-vararg

[Hama Kamal]

hey folks

it seems like the compiler cant choose between wide-vararg or box-vararg?! when i try to compile below code i get : something like reference to vararg is ambiguos!

class Vararg {
static void vararg(long... x)
{ System.out.println("long..."); }
static void vararg(Integer... x)
{ System.out.println("Integer..."); }
public static void main(String [] args) {
int i = 5;
vararg(i); // if choses the first method it needs to be widen and then vararged but if it choses the second one it needs to be boxed and then vararged!

}
}

[Seetharaman Venkatasamy]

Dive Here

[Hama Kamal]

Seetharaman Venkatasamy wrote:Dive Here

thanks dude ,

[Seetharaman Venkatasamy]

Hama Kamal wrote:thanks dude

You are welcome dude