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default case in switch matches all the case

 
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In the following code , default case is written first so i think this will execute no matter the value of expression is .
But the output says something else.
here's the code


Kindly correct me.
 
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The default case is only chosen as 'entry' point if no other case matches the value of i independent of where the default case appears . So in the case of i = 10 the entry point is case 10:.

John
 
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