Hi,
My action form bean code is like this
class searchProjectForm{
serchProjectForm(){
//constructor
}
Public void reset(ActionForm form,HttpServletRequest request){
super.reset(request);
//array declaration
}
public void setSurName(
String surname){
this.surname=surname;
}
public String getSurName(){
return surName
}
and the code for JSP is
searchProject {
<html:javascript formName="searchProjectForm" method="validateSearchProjectForm"/>
<html:form action="/searchProjectRelay" onsubmit="return validateSearchProjectForm(this);">
<html:hidden name="searchProjectForm" property="dispatch"/>
<html:hidden name="searchProjectForm" property="mode"/>
<html:hidden name="searchProjectForm" property="filterID"/>
<html:hidden name="searchProjectForm" property="filterName"/>
<ournet:button name="SearchProjectFind" displayName="Find" dispatch="SearchProjectFind" page="SearchProject" form="searchProjectForm"/>
<tr>
<td align="right"><b><i>Assigned User - AU -</i></b>(blank = ALL) Surname</td>
<td><html:text property="surName" maxlength="20" size="20"/></td>
</tr>
and my action class code is
public class PerformSearchProjectAction extends PLOAction {
protected String doExecute(ActionForm form, HttpServletRequest request) throws Exception {
_log.debug("Entering PerformSearchProjectAction.doExecute(...)");
if (!(form instanceof SearchProjectForm)) { // We do not have a SearchProjectForm, so we
// cannot feasibly continue
return NPAAction.FAILURE_KEY;
}
else {
SearchProjectForm searchProjectForm = (SearchProjectForm) form;
try{
projectSearchFormulator.setAssignedUserSurname(searchProjectForm.getSurName());
} }
catch (Exception e) {
e.printStackTrace();
_log.debug("In PerformSearchProjectAction.doExecute(...) - Exception: " + e);
return NPAAction.FAILURE_KEY;
}
_log.debug("Exiting PerformSearchProjectAction.doExecute(...)");
return NPAAction.SUCCESS_KEY;
}}
Any Help Would be appreciate