Why does a constructor call another construtor automatically ?

[WeiJie Lim]

When I executed Trial1.java, the out.println message "Success! Trial2(String s1) " prints out, which means that the empty Trial2 constructor automatically calls the 2nd Trial2 constructor.

Why does it do it ? I don't understand.

Any guidance is appreciated.

Code for Trial1.java.

public class Trial1 {
	
	public static void main(String[] args) {
		
		Trial2 var1 = new Trial2();
	}

}

Code for Trial2.java

public class Trial2 {

public Trial2(){
		this("b");
	}
	
	public Trial2(String s1){
		System.out.println("Success! Trial2(String s1) ");
	}

}

[Jesper de Jong]

It isn't calling the other constructor automatically. Look at line 4 of Trial2.java. From the no-args constructor of Trial2, you're calling the other constructor there explicitly, with: this("b");

[WeiJie Lim]

Jesper de Jong wrote:It isn't calling the other constructor automatically. Look at line 4 of Trial2.java. From the no-args constructor of Trial2, you're calling the other constructor there explicitly, with: this("b");

Thanks, I didn't know this is due to the this keyword. Found out that the this keyword can call another constructor in the same class.

[manish ghildiyal]

WeiJie Lim wrote:Thanks, I didn't know this is due to the this keyword. Found out that the this keyword can call another constructor in the same class.

...yes. this keyword makes you call the other constructor.