Sundar Murthi

Hi

The following qn found in one of the mock exam
what is the output

public Class Q1{ int i=20 static{ int i=10; } public static void main(String []args){ Q1 a=new Q1(); System.out.println(a.i); } }
what is the output?

My view is
its a compiler error
but the ans is "it prints 20"

how it is?

actualy
static{
}
is not a method its a block of code
how the variable i declared with in i is ignored..

tx in adv..

How many threads are started in the code at label is reached

class Test implements Runnable{ public static void main(String args[]){ Thread t1=new Thread(new Test()); Thread t2=new Thread(new Test()); t1.run(); t1.run(); //label } public void run(){ System.out.println("some thing"); try{ Thread.currentThread().sleep(500); }catch(Exception e){} } }

i know that while calling run() method no thread was created.
it is just a method calling

but the ans given is

one thread is started how it is

Hi Corey
I understand the purpose of intern() method and get the result as true.
It creat a new string if it is not exists in a string pool. If exists its refference is returned.

Still i have the problem

look at the following one

("Hello".replace('e','e')=="Hello")
it returns true

and
[CODE]
String str="Hello";
(str.replace('e','e')=="Hello")
[CODE]

it returns false

How it is??

Hi Shilpi
Kai's notes it self given a good explanation for that one

and many more discussions and sample codes in kai notes(last edited by 2000) contains bugs
dont wory about it