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IBM WSAD...error
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Pappu Kumar
Ranch Hand
Joined: Oct 01, 2002
Posts: 69
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Hi guys , i had posted a DataSource question before...but i was able to figure that out. My new problem is that i cant get the DataSource object in my java program and the following error is thrown. --------------------------------------------------- java.lang.NoClassDefFoundError: com/ibm/ejs/ras/TraceElement at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:212) at com.sun.naming.internal.VersionHelper12.loadClass(VersionHelper12.java:46) at javax.naming.spi.NamingManager.getInitialContext(NamingManager.java:656) at javax.naming.InitialContext.getDefaultInitCtx(InitialContext.java:247) at javax.naming.InitialContext.init(InitialContext.java:223) at javax.naming.InitialContext.<init>(InitialContext.java:199) at DataSourceCheck.main(DataSourceCheck.java:27) Exception in thread "main" -------------------------------------------------- Here is my Java program : import java.sql.*; import javax.naming.*; import java.util.*; class DataSourceCheck { public static void main(String[] args) { javax.sql.DataSource myDataSource= null; try { String initialContextFactory = "com.ibm.websphere.naming.WsnInitialContextFactory"; String providerURL = "iiop://localhost:8081"; java.util.Properties props = new java.util.Properties(); props.put(Context.INITIAL_CONTEXT_FACTORY, initialContextFactory); props.put(Context.PROVIDER_URL, providerURL); Context myContext = new InitialContext(props); Connection myConnection = myDataSource.getConnection(); } catch (Exception e) { e.printStackTrace(); System.out.println(); } } } ------------------------------------------------- I start a Server instance from IBM WSAD and it runs on 8081. Please suggest what to do .
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Kyle Brown
author
Ranch Hand
Joined: Aug 10, 2001
Posts: 3878
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OK, the issue here is that when you just run a Java program in WSAD you're not starting it within WebSphere's J2EE client container. This is a common question we address in the WebSphere forum every day or so. Inside WSAD, the way you address this is to make sure you do two things: (1) Your client program must be within an Application Client Project associated with an EAR Project. (2) To Run your client, first start the server. Then select your client program class (the one with the main() method) inside the J2EE perspective. Open the Run menu at the top of the screen and select "Run..." (Make sure you select Run... and not Run As). (3) In the launch Configurations panel, select "WebSphere 5 Application Client" and press the "New" Button. Give your configuration a name (other than "new configuration" -- I usually use the same name as the client program class). If there are program arguments,enter them in the arguments tab. Hit "Apply" and the new configuration will be added. (4) To run the client, press the "Run" button on ths page. Note this will ONLY work if you are in WSAD 5.0. If you are in WSAD 4.0, you need to follow the instructions in this article. Kyle [ March 18, 2003: Message edited by: Kyle Brown ]
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Kyle Brown, Author of Persistence in the Enterprise and Enterprise Java Programming with IBM Websphere, 2nd Edition
See my homepage at http://www.kyle-brown.com/ for other WebSphere information.
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subject: IBM WSAD...error
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