What is the difference between two path task code?

[Ayse Muge]

Hi all,

In source folder, there are java files to compile. They need to use some jar files I defined under the lib folder.

what is the difference between 2 code? I think there is no difference but first one is ok,it works; but second one is not working. Instead of writing jar files name one by one, I define all files in one step in second code for javac task which jar files it needs to use.Ignore my folder values there is no problem. My problem is how can I define my all jar files in one step?

Any suggestion?
Thnx


<path id="designer.path">
<pathelement location="lib/cs_mdi.jar"/>
<pathelement location="lib/csfc.jar"/>
<pathelement location="lib/debugger.jar"/>
<pathelement location="lib/jbcl.jar"/>
<pathelement location="lib/lf.jar"/>
<pathelement location="lib/UID.jar"/>
<pathelement location="lib/xerces.jar"/>
<pathelement location="lib/JavaRenderer.jar"/>
</path>

----------------------------------------------------------------

<path id="designer.path">
<pathelement location="lib/*.jar"/>
</path>


the following code is in javac task. I used classpathref attribute in here:

<target name="build" depends="checkpack">
<javac srcdir="${LclFldrSrc}" destdir="${LclFldrDest}" classpathref="designer.path"/>
</target>

[Dirk Schreckmann]

I'm not sure if pathelement supports all of the patterns that something like fileset or patternset would. Why not try using a fileset instead?

<path id="designer.path">
  <fileset dir="lib">
    <include name="lib/*.jar"/>
  </fileset>
</path>

[ July 22, 2004: Message edited by: Dirk Schreckmann ]