Running Dependent Jobs in Unix

[Rishi Chopra]

All,

I have a shell script that gets kicked off at 8:00 which runs a java program
This java program finishes its task around 8:40 (this is not a certain time can finish earlier or get delayed as well)

I have another shell script that has to be made run directly after the above shell script. This script also runs a java process.

Since i really dont have too much hands on experience in Unix so dont know how to run dependent jobs

Also ,

The first process again runs at 12:00 and finishes around 12:40 or something . After this as well i need to kick off my second process

Please Help

Thanks & Regards
Rishi Chopra.

[Tim Holloway]

The simplest way to do that is simply to create a new script that calls the other 2 scripts one after the other and make it be the cron job script.

[Stefan Wagner]

If the second should just run if the first was successful (dependent), combine both with && (like in java):

#/bin/bash
script1.sh && script2.sh
 

If script1 fails script2 will not be called - assuming either outher circumstances terminating script1, or using the exitstatus in your java programs (System.exit (0) := no error, System.exit (i); // i != 0, i := an errorcode).

[Rishi Chopra]

Thanks All