Java - Overloading and Overriding of methods

[Paras Shah]

Below is the code

<font size=+0>
class Base {
int i;
Base() {
System.out.println("Inside Base func");
add(1);
}
void add(int v){
System.out.println("Inside Base:Add func " + v);
i += v;
}
void print(){
System.out.println(i);
}
}
class Extension extends Base {
Extension() {
System.out.println("Inside Extension func");
add(2);
}
void add(int v){
System.out.println("Inside Extension:Add func " + v);
i += v * 2;
System.out.println("Inside Extension func:Value of i " + i);
}
}
public class test {
public static void main(String[] args) {
System.out.println("Before");
bogo(new Extension());
}
static void bogo(Base b) {
b.add(8);
b.print();
}
}</font>

The output is 22.
What is the flow of this program ??
[This message has been edited by Marilyn deQueiroz (edited July 24, 2001).]

[Marilyn de Queiroz]

moved to Java in General (beginning)