I've these lines:where i am loafing CSS within my xsl <!--LOAD THREE STYLESHEETS, 1 COMMON, 1 FOR NETSCAPE, 1 FOR IE--> <link rel="stylesheet" type="text/css" href="w3_common.css" /> <link rel="stylesheet" type="text/css" href="w3_netscape.css" disabled /> I get the error Attribute name "link" must be followed by the '=' character but that doesnt work - does anyone have any Idea - I've tried this as well <xsl:text><link rel="stylesheet" type="text/css" href="/JSP/w3_common.css" ></xsl:text> <xsl:text><link rel="stylesheet" type="text/css" href="/JSP/w3_netscape.css" disabled ></xsl:text> but in this I dont get displayed the output
any help would be really appreciated Arsalan
Arsalan Lodhi
Greenhorn
Joined: Jul 05, 2001
Posts: 4
posted
0
Okay - I got my answer ! for detail goto http://www.w3.org/TR/xml-stylesheet/ Here are the example from HTML 4.0 with the corresponding processing instruction: <LINK href="mystyle.css" rel="style sheet" type="text/css"> <?xml-stylesheet href="mystyle.css" type="text/css"?>