Dear All, i have a jsp which transforms an xml file with an xsl.My xml file contains more than 50 records.I need to display only 10 records instead of a all the 50 records to the user. Questions: 1.Do we have functions in jaxp api that can help pass the parameters to the xsl file or any other method to implement this using java api's only? 2.How to achieve this in xsl file itself?
author and deputy
posted 13 years ago
If you are using XALAN,there is servlet example in the docs folder which shows how to pass XSL parameter with querystring. rgds balaji