Hi, I have an XML file like the following. I need to write an XSL file which will display the following columns of every tag(<col> under each tag(<row> . How do I do this? My sample XSL is also posted below XML which does not display the xml info in the table. Please help me. </RowSet> <data> <row> <col>7369</col> <col>SMITH</col> <col>CLERK</col> </row> <row> <col>7499</col> <col>ALLEN</col> <col>SALESMAN</col> </row> <row> <col>7521</col> <col>WARD</col> <col>SALESMAN</col> </row> </data> </RowSet> XSL: <?xml version="1.0" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template match="row"> <HTML> <BODY> <CENTER> <TABLE> <TR> <TD> <FONT COLOR="#CC0000" SIZE="+1"> <B>List of Products</B> </FONT> </TD> </TR> <TR> <TD> <xsl:for-each select="/RowSet/data/row"> <xsl:value-of select="col"/> </xsl:for-each> </TD> </TR> </TABLE> <BR/> <FORM ACTION="../jsps/Main.jsp" METHOD="post"> <CENTER> <INPUT TYPE="SUBMIT" NAME="Back" VALUE="Back To Main Page"/> </CENTER> </FORM> </CENTER> </BODY> </HTML> </xsl:template> </xsl:stylesheet> Thank you and regards, Raj.
Ron Newman
Ranch Hand
Joined: Jun 06, 2002
Posts: 1056
posted
0
You're matching on "row", but you're also doing a foreach on /RowSet/data/row . Do one or the other, not both.
Ron Newman - SCJP 1.2 (100%, 7 August 2002)
Naren
Greenhorn
Joined: Jul 21, 2003
Posts: 23
posted
0
Replace the corresponding lines with these:
<xsl:template match="data"> =========================== <xsl:for-each select="row"> ============================ That's all. It will work :roll:
<a href="http://www.mqtips.com" target="_blank" rel="nofollow">MQMessenger</a> - free Java app for MQSeries
I agree. Here's the link: http://ej-technologies/jprofiler - if it wasn't for jprofiler, we would need to
run our stuff on 16 servers instead of 3.
0
under each tag(<row> 
