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XPath with variables

Ranch Hand

Joined: Nov 22, 2008
Posts: 18944
Hi there,
I have a XML file that looks like this:

I have a stylesheet, that looks like that:

I would like to change the XPath Expression to point the language that is in curLanguage. I tried

but without success. How does the correct XPath look like?
;-) stw

Disabled smiles.
- m
[ June 29, 2004: Message edited by: Madhav Lakkapragada ]
Nimchi Yung
Ranch Hand

Joined: Jan 27, 2004
Posts: 71
<xsl:template match="priorities"><xsl aram name="curLanguage"/><xsl aram name="curPrio"/><xsl:value-ofselect="priority-key[level=$curPrio]/English"/></xsl:template>

I think your XPath expr should be like this:

Ranch Hand

Joined: Nov 22, 2008
Posts: 18944
Hi Nimchi,
thx for taking the time to reply. From your reply I see, that I didn't phrase my question clearly. The xpath
actually does work well. What I want to achieve is to replace English by the content that is in $curLanguage.
This is a very fundamental problem for me: how to construct an xPath expression where the name of a node is a variable. I tried to poke around with the name() function but no luck. The w3school tutorials didn't answer this question too (or I missed it).
;-) stw
Porky Liu

Joined: Jan 30, 2002
Posts: 22
maybe you can get all the element under priority-key, and then get the correct element with xsl:if test current() = $whatever, just like this

It's not easy, but I do think it can work
Ranch Hand

Joined: Nov 22, 2008
Posts: 18944
Hi Porky Liu,

thx for your reply. I did a little reevaluating of XLST concepts. You actually can't compare a node to a string. So the solution is to look for something that is a string inside the node. The riddle is solved when you use the name() function. to the answer is:

;-) stw
[ July 07, 2004: Message edited by: Stephan H. Wissel ]
It is sorta covered in the JavaRanch Style Guide.
subject: XPath with variables
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