SAX -- DOM?

[Ernest Friedman-Hill]

I'm working on implementing a badly-designed API. I find myself in a spot where I've got a SAX parser for a given document format, and I need to implement a method that's handing me an org.w3c.dom.Element representing the root of a DOM model for that same format.

Without writing a DOM version of the parser, and without bouncing the DOM off the disk as XML (which itself is far trickier than it ought to be -- ) is there any relatively simple way, using only API classes, to walk the DOM tree and feed the SAX parser?

[Jim Yingst]

Something like this, I guess:

Source source = new DOMSource(rootNode);
Result result = new SAXResult(contentHandler);
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.transform(source, result);

[Ernest Friedman-Hill]

Works great! I knew there had to be an easy way to do this!

[Jim Yingst]

Cool. Note that if you do find yourself needing to convert to/from XML, you may also want to look at StreamResult and StreamSource.