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XML Comparison without DTD & XSD and able to return XPath of the Diff Node

saravanan periasamy
Greenhorn

Joined: Feb 06, 2005
Posts: 22
Dear All,

I am new xml concept in java.

First xml can have n of nodes and second xml can have n of the node.
The node is new to second xml when compare to first xml.It has to go change list.

1. I need to compare 2 xml document and return the XPath of the Nodes.

2. Both xml do not have any association like XSD,DTD and XSLT.

3. I am looking for java api to find/return xpath of the node.

Please help me.
Saravanan.P
 
It is sorta covered in the JavaRanch Style Guide.
 
subject: XML Comparison without DTD & XSD and able to return XPath of the Diff Node
 
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