A friendly place for programming greenhorns!
Big Moose Saloon
Register / Login
Win a copy of
video training course this week in the
XML and Related Technologies
XML Comparison without DTD & XSD and able to return XPath of the Diff Node
Joined: Feb 06, 2005
May 29, 2007 03:40:00
I am new xml concept in
First xml can have n of nodes and second xml can have n of the node.
The node is new to second xml when compare to first xml.It has to go change list.
1. I need to compare 2 xml document and return the XPath of the Nodes.
2. Both xml do not have any association like XSD,DTD and XSLT.
3. I am looking for
java api to find/return xpath of the node.
Please help me.
It is sorta covered in the
JavaRanch Style Guide
subject: XML Comparison without DTD & XSD and able to return XPath of the Diff Node
How can i get XPath of the XML Node using Java API without DTD and XSD
Wanted: minimal XPath sample
XPath expression constrained by a predicate doesn't work (//element[@attribute="value"])
How to update/insert/delete an element from an XML document
override the equals and hashcode
All times are in JavaRanch time: GMT-6 in summer, GMT-7 in winter
| Powered by
Copyright © 1998-2015