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XML Comparison without DTD & XSD and able to return XPath of the Diff Node
Joined: Feb 06, 2005
May 29, 2007 03:40:00
I am new xml concept in
First xml can have n of nodes and second xml can have n of the node.
The node is new to second xml when compare to first xml.It has to go change list.
1. I need to compare 2 xml document and return the XPath of the Nodes.
2. Both xml do not have any association like XSD,DTD and XSLT.
3. I am looking for
java api to find/return xpath of the node.
Please help me.
I agree. Here's the link:
subject: XML Comparison without DTD & XSD and able to return XPath of the Diff Node
How can i get XPath of the XML Node using Java API without DTD and XSD
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