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JavaRanch » Java Forums » Engineering » XML and Related Technologies
Bookmark "SAXParseException" Watch "SAXParseException" New topic
Author

SAXParseException

Milan Vasic
Greenhorn

Joined: May 23, 2008
Posts: 3
Hi there this is my code:

<jsp:root xmlns:jsp="http://java.sun.com/JSP/Page" version="2.0">
<jsp:directive.page contentType="text/html; charset=UTF-8" />
<jsputput doctype-root-element="html"
doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
doctype-system="http://www.w3c.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">

some html code....


</html>
</jsp:root>


I still got the exception :org.xml.sax.SAXParseException: The markup in the document following the root element must be well-formed. Doeas anyone know why?
William Brogden
Author and all-around good cowpoke
Rancher

Joined: Mar 22, 2000
Posts: 12982
    
    5
There are methods in SAXParseException to get the line and column number that the parser objects to.

Bill
Milan Vasic
Greenhorn

Joined: May 23, 2008
Posts: 3
Tnx Bill.

vaske
Milan Vasic
Greenhorn

Joined: May 23, 2008
Posts: 3
I try to validate my jsp with a loot of on line validators, and my jsp is well formated, but when I try to parse that file with parse method on documentbuilder object I got this error.
William Brogden
Author and all-around good cowpoke
Rancher

Joined: Mar 22, 2000
Posts: 12982
    
    5
Have you been able to extract the line and column from the exception?
How is the jsp source code being generated?

Bill
 
It is sorta covered in the JavaRanch Style Guide.
 
subject: SAXParseException
 
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