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SAXParseException
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Milan Vasic
Greenhorn
Joined: May 23, 2008
Posts: 3
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Hi there this is my code:
<jsp:root xmlns:jsp="http://java.sun.com/JSP/Page" version="2.0">
<jsp:directive.page contentType="text/html; charset=UTF-8" />
<jsp utput doctype-root-element="html"
doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
doctype-system="http://www.w3c.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
some html code....
</html>
</jsp:root>
I still got the exception :org.xml.sax.SAXParseException: The markup in the document following the root element must be well-formed. Doeas anyone know why?
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William Brogden
Author and all-around good cowpoke
Rancher
Joined: Mar 22, 2000
Posts: 12265
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There are methods in SAXParseException to get the line and column number that the parser objects to.
Bill
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Java Resources at www.wbrogden.com
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Milan Vasic
Greenhorn
Joined: May 23, 2008
Posts: 3
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Tnx Bill.
vaske
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Milan Vasic
Greenhorn
Joined: May 23, 2008
Posts: 3
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I try to validate my jsp with a loot of on line validators, and my jsp is well formated, but when I try to parse that file with parse method on documentbuilder object I got this error.
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William Brogden
Author and all-around good cowpoke
Rancher
Joined: Mar 22, 2000
Posts: 12265
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Have you been able to extract the line and column from the exception?
How is the jsp source code being generated?
Bill
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subject: SAXParseException
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