Java Rules Round #154

[Win jones]

Question )
Assuming all variables are declared and initialized properly will the following code compile
for (i = 1; k <5;j++){};

why is there a semi-colon after the last curly brace
because of that the code will not compile

[Mukesh Poddar]

As your Question itself says ...all the variables i,j,k are declared and initialized properly.....
The program will run Succesfully.....

Since in Java an ; separates the One statement from the other......

And the Bracket before the "{}" dosen't signify anything it just gives compiler the infiormation that a new block is started....

so te compiler will treate as a null statement.... and compile the program succesfully.....

[amit taneja]

just tell me that
whether
;
statement in java program will not cause compiler error ?
just asking...

[Marilyn de Queiroz]

Originally posted by amit taneja:
just tell me that
whether
;
statement in java program will not cause compiler error ?

An extra semicolon after the curly brace will not cause a compiler error.

[Rick O'Shay]

Originally posted by amit taneja:
just tell me that
whether
;
statement in java program will not cause compiler error ?
just asking...

The semicolon designates an empty statement:

// OK
class Foo {
void bar() {}
int x;
}

// OK
class Foo {
void bar() {}
;
}

// OK
class Foo {
void bar() {};
}

// OK
class Foo {
;;;;;;;;;;;void bar(){;;};;;;;;;;;;;;;;;;;;;;
}