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Confusion on code

Sushanta Chakrabarty
Greenhorn

Joined: Dec 05, 2007
Posts: 4
public class DDg {

public static void main(String[]args){
fgh f = new fgh();
f.fgr(new Iface(){ public void ggg(){System.out.println("a");}});

}

}
interface Iface{
void ggg();

}
class fgh{
void fgr(Iface I){System.out.println("b");}
}

In the above mentioned program I think I should get "a" as output but I am getting "b". May anyone help?
HarrySingh
Greenhorn

Joined: Nov 29, 2007
Posts: 1
f.fgr(new Iface(){ public void ggg(){System.out.println("a");}});

You are calling fgr() method which takes instance of Iface which is an interface so you have to create an anonymous inner class inside the argument BUT you are never made a call ggg() in your code.
 
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subject: Confusion on code
 
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