Thread doubt

[Sushanta Chakrabarty]

Hi,

I am getting StackOverflowException when I run the following code.

Sushanta.

public class EE extends Thread{
EE e = new EE();
void q(){
synchronized(e){
try{
wait();
}
catch(Exception ex){}
}}
public static void main(String[]args){
EE e = new EE();
e.q();
}
}

[Chris Hurst]

IN your main, you create an EE, your EE has a EE member that in turn has an EE
member which in turn has an EE member which repeats to infinity ... or in your case your stack overflows.

Basically one of your new EE's shouldn't be there at a guess remove the member variable one and make the method sync on

this

instead.

PS in 'real' code wait should always be in a loop testing an appropriate variable.

[ajay verma]

you should use super keyword in order to pass from super class

[Nicholas Jordan]

I think your stack overflow derives somehow from havign two calls that look like this: EE e = new EE(); The rest is as given.

Most stack overflows descend somehow from this type of control-flow/logic-error mistake that looks like this.
[ March 30, 2008: Message edited by: Nicholas Jordan ]