Dear Ranchers, After changing context path in server.xml - has no effect. I still need to include it in the path. Note that webapp1 is in the webapps dir. ie. c:\Tomcat4\webapps\webapp1 // Excerpt from server.xml <!-- Tomcat Root Context --> <!-- <Context path="/webapp1" docBase="webapp1" debug="0" reloadable ="true" /> --> Do I have to uncomment the above? Ive tried it still has no effect. I would like to access my apps by: http://localhost/jsp-file where jsp-file sits in the webapp1 directory. Can anyone advise? Regards Stephen Batsas SCPJ2
<!-- Tomcat Examples Context --> <Context path="/webapp1" docBase="webapp1" debug="0" reloadable="true" crossContext="true"> <Logger className="org.apache.catalina.logger.FileLogger" prefix="localhost_examples_log." suffix=".txt" timestamp="true"/>------------------------ 2)if it is done properly you have to call your jsp stop and restart server again then call http:/localhost:8080/webapp1/file.jsp 3)if you are doing on windows98 some times it will not work .I don't know why. but on winNT it will work perfectly
After changing context path in server.xml - has no effect. I still need to include it in the path.
However I have explained below the addition of a new context to server.xml: To add a context for c:\Tomcat4\webapps\webapp1, you have to add the following in server.xml at the appropriate place. <Context path="/webapp1" docBase="webapp1" debug="0" reloadable="true"> </Context> Then restart/start tomcat server and access the files in webapp1 using "/webapp1" prefix. That is, to access a file say, send.jsp, use [URL=http://localhost:no/webapp1/send.jsp, where no is the port number to which tomcat server has been configured to listen. Hope this helps. Gaja Venkat -------------------------------------------- Sun Certified Programmer for Java 2 Platform [ March 19, 2002: Message edited by: Gaja Venkat ]
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