hi : I have got a question when I try to practice how to use getOutputStream in the following example. The question is where shall I put the file bart.gif. I tried several location such as /WEB-INF/classes , docment-root. It always complains to me "file not found". Any thoughts on that. Thank you.
Grant: I tried this with a jpg (image/jpg - mime type). The file was directly under the Web application DocumentRoot. I also got the same error. Only thing i changed is used a forward slash just before the image file name. So I guess in your case you would use
File f = new File ("/bart.gif")
Joined: Aug 13, 2001
Grant: I need to recant my suggestions in the previous post. It then worked because my file was in the root drive (d:\). I realized and tested out that when you create a File instance the argument must be a path to the file you want to create File instance upon. So in your case it should be as follows: File f = new File ("d:\\whateverdir\\whateversubfolder\\bart.gif"); I am using W2K hence the above file path. I think your best bet for portablity and all is to use the getRequestDispatcher() and/or getNamedDispatcher() methods of ServletContext object. HTH