I am kind of getting conused about installing Tomcat. There were three files in the tomcat.apache website. 1.zip file 2.tar file 3.Windows Service Installed (exe file)
I had downloaded the zip and the exe file . And then installed the exe file, which created a "C:/Program Files/Apache Software Foundation/Tomcat 5.5/* files.
However I later realised i did not have the startup.batch file required for starting up in the C:/Program Files/Apache Software Foundation/Tomcat 5.5/bin directory.
It was present in the zip file which I had unzipped (but never used) And was present in the apache-tomcat5.527/bin directory.
I am not sure which file is what and what is each used for.
Can some one please clarify the installation process. [ October 20, 2008: Message edited by: Nabila Mohammad ]
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You need to installer either the ZIP or the EXE, not both. If you are using Windows, I recommend you to get the Windows Service Installer. It will set environment variables for you, and you will be able to start/stop the server from the task tray. It won't come with a startup.bat, because you can start the server via Windows Start menu (Monitor Tomcat).
I did start Tomcat via Start up option But still getting the error Internet Explorer cannot display page wehn i I type http://localhost:8080/ch1/Serv1
Nabila Mohammad
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I also cannot view the Web.xml file.
I get the error :
The XML page cannot be displayed Cannot view XML input using style sheet. Please correct the error and then click the Refresh button, or try again later.
System does not support the specified encoding. Error processing resource 'file:///C:/Documents and Settings/S...
<?xml version="1.0" encoding="ISO-8851-1" ?> However, when i change encoding="ISO-8851-1" to encoding="UTF-8" I can view the xml file.