Strings

[Anonymous]

Hi,
Can anyone, tell me what does the following code mean:
String c="a";
String d = (c + "aaa").intern();

[Michal Harezlak]

<code>String c="a";</code>
// assignees a reference to the String "a" to c.
<code>String d = (c + "aaa").intern();</code>
// concatenates "a" and "aaa", creates String "aaaa"
// places in tnto VM internal string pool
// assignees a reference to String "aaaa" to d.
check what will happened with this code:
1.
<code>
String c="a";
String d = (c + "aaa").intern();
String e = "aaaa";
System.out.print(e=d)
</code>
1.
<code>
String c="a";
String d = (c + "aaa").intern();
String e = "aaaa";
System.out.print(e=d)
</code>
read about String class in

Java Platform specification

[Michal Harezlak]

should be:
2.
<code>
String c="a";
String d = (c + "aaa");
String e = "aaaa";
System.out.print(e=d)
</code>

[Michal Harezlak]

and one more :-(((
2.
<code>
String c="a";
String d = (c + "aaa");
String e = "aaaa";
System.out.print(e==d)
</code>

[Anonymous]

Originally posted by Michal Harezlak:
<code>String c="a";</code>
// assignees a reference to the String "a" to c.
<code>String d = (c + "aaa").intern();</code>
// concatenates "a" and "aaa", creates String "aaaa"
// places in tnto VM internal string pool
// assignees a reference to String "aaaa" to d.
check what will happened with this code:
[b]1.
<code>
String c="a";
String d = (c + "aaa").intern();
String e = "aaaa";
System.out.print(e=d)
</code>
1.
<code>
String c="a";
String d = (c + "aaa").intern();
String e = "aaaa";
System.out.print(e=d)
</code>
read about String class in

Java Platform specification[/B]

Thanks for ur reply! Does that mean that now d and c will
now have the same reference (since VM places d in the same
string pool.)

[Jim Yingst]

Exactly.
Michal- if you register for a JavaRanch account, you will be able to edit your messages after you post them, which as you see can be useful at times.