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hello kanan, the explanation to this output goes like this. if(b= i == j) remember 1) during assignment operation (i.e. '=' operation )first of all the RHS expression is calculated and the result is assigned to LHS. so in ur case RHS expression is i==j which is true so now the if(...) becomes if(b = true) now true will be assigned to b so finally if(...) will be considered if(true) so the expression inside if() has value true so the output is true. hope this explain things. do post any other doubt of urs. regards deekasha

int i = 10; int j = 10; boolean b = false; if(b= i == j) System.out.println("True"); else System.out.println("False"); To make the if statement more clear, look at it this way: if(b = (i==j)) Here, i==j returns true, which is assigned to b. Now, your if statement has its required boolean condition - b - which is true. Hence the result.

Kanan Jariwala
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Joined: Jun 22, 2000
Posts: 17

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thanks deeksha and gopinath, u'll explained that one fine

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