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# another Mock Exam Question

Gaurav Chikara
Ranch Hand
Posts: 412
Hi all
This is a question from Mock Exam
1 String s = null;
2 if ( s != null & s.length() > 0)
3 System.out.println("s != null & s.length() > 0");
4 if ( s != null && s.length() > 0)
5 System.out.println("s != null & s.length() > 0");
6 if ( s != null | | s.length() > 0)
7 System.out.println("s != null & s.length() > 0");
8 if ( s != null | s.length() > 0)
9 System.out.println("s != null | s.length() > 0");
Which of the following lines throwing null pointer exception

A. 2,4
B. 6,8
C. 2,4,6,8
D. 2,6,8
Correct answer is D
But I could not get logic behind it clearly
Can anyone be of any help in this regard ?

Greenhorn
Posts: 13
A logical OR operator '|' and a logical AND '&' operator evaluates both the expressions and therefore java compiler throws a nullpointerException while evaluating the 's.length()' statement as s is set to null. But in a short Circuited(&&) operator if the 1st condition is true it evaluates the next condition and gives the exception but in a short circuited (| |) operator if the first condition is true the it dosnt evaluate the next condition hence the exception is not thrown.

pardha
Greenhorn
Posts: 11
Refer Short Circuit operators (| | ,&&),in these operators ,decision to execute the second expression is based on the result of the first one.
Normal operators (&,|)will evaluate both the expressions.
At line 2, s.length() is evaluated and results in exception.
At line 4,s.length() is not evaluated because the first one is false.
At line 6,s.length() is evaluated as the first expression is false.
At line 8,s.length() is evaluated.