Majji Mock Q #9

[KN]

Hi,
I have a doubt in this question.
The following code will give:
Byte b1 = new Byte("127");
if(b1.toString() == b1.toString())
System.out.println("True");
else
System.out.println("False");
A. compilation error, toString() is not available for Byte.
B. prints "True".
C. prints "false".
The given ans. is C. & it's correct. Can somebody explain me why? They are referring to the same object. Shouldn't it return true.
Thanks,
Kiran.

[thomas]

They are NOT refering to the same object. Note that the method Byte.toString() returns a NEW String object representing the byte value. Each time you use it, it creates a new String object.

[KN]

Thanks Thomas. I somehow missed that point.
Regards,
Kiran.