explain this string method..

if(" String ".trim() == "String")
System.out.println("Equal");
else
System.out.println("Not Equal");
why this is printing not equal, because when string is trimmed
it should be equal to String..,
can someone explain

Originally posted by Bhasker Reddy:
if(" String ".trim() == "String")
System.out.println("Equal");
else
System.out.println("Not Equal");
why this is printing not equal, because when string is trimmed
it should be equal to String..,
can someone explain

I think you need to read the chapter on "Strings" once more.
This is the most basic thing, here you are trying to compare the addresses of the two strings with the operator ==. I you want to compare the strings as such(the contents of the strings), you need to use the method - equals() as:
" String ".trim().equals("String")
- you will get the correct result.

the following code will print Equal
if ("String"=="String")System.out.println("Equal");

because there is only one string object is created.
This is equivalent to saying,

String a="String";
String b="String";
if (a==b) System.out.println("Equal"); // will print Equal

But " String ".trim()=="String" is not equal because
" String ".trim() creates a new String object.
This is equivalent to

String a="String";
String b=new String("String");
if (a==b) System.out.println("Equal");
else System.out.println("Not Equal"); // will print not equal

What about
String a=new String("String");;
String b=new String("String");
if (a==b)
System.out.println("Equal");
else
System.out.println("Not Equal");
It stills prints Not Equal. I thought this time it should point to the same memory address.
Your inputs will be highly appreciated.

String a=new String("String");
String b=new String("String");
The above code creates 2 string objects.
The following mock exam has a lot of questions on string equality.
http://members.theglobe.com/apoddar/questions.html

Thanks Srini
I need to do a lot of reading and practice cos I'm giving exam on Aug 18.
THanks again