?: operator

[anchal jain]

try this:
byte b=true?1:12345; //OK
b=false?1:12345; //Error at compiling
Look at JLS Chapter 15 about ?:, and my understanding
is neither of above should pass compiling.
It's a bug or something else?

[MahaAdd]

Hi,
the 2nd statement doesn't compile because when false it assigns a number 12345, which is out of the range for a byte ( -128 to 127 ).
the 1st statement compiles because when true it assigns 1 to b.(where the value is within the byte range)

and a boolean value can be assigned to a byte...both are 8 bits long.

Originally posted by learner:
try this:
byte b=true?1:12345; //OK
b=false?1:12345; //Error at compiling
Look at JLS Chapter 15 about ?:, and my understanding
is neither of above should pass compiling.
It's a bug or something else?

[Ada Wang]

My personal understanding is: the statement (a = x ? b : c) is directly equivalent to the textually longer version:
1. if (x) {
2. a=b;
3. }
4. else {
5. a=c;
6. }

For your case, (bype b = true ? 1 : 12345) is equivalent to :
if true {
bype b=1;}
else {
bype b=12345;
}
Hopefully, I answered your question.
Ada