If write(0x01234567) is called on an instance of OutputStream, what will be written to the destination of the stream?Select the right answer. Any takers?? a The bytes 0x01, 0x23, 0x34, 0x45, and 0x67, in that order. b The bytes 0x67, 0x45, 0x34, 0x23, and 0x01, in that order. c The byte 0x01.
I would first go to the Java API docs and if still unsatisfied, I would write a small prog. and test it out. Anyway, the API says: public abstract void write(int b) throws IOException Writes the specified byte to this output stream. The general contract for write is that one byte is written to the output stream. The byte to be written is the eight low-order bits of the argument b. The 24 high-order bits of b are ignored. Subclasses of OutputStream must provide an implementation for this method. This means it would only write 0x67. HTH, Paul. ------------------ http://pages.about.com/jqplus Get Certified, Guaranteed!