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Roundup #13 answer explanation not totally right

 
Serge Plourde
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#13 Assume: byte a=3; byte b=2; What is the result
of: byte c=a+b;
Answer: compiler error
The result of arithmetic is always at LEAST an int,
so the compiler will ask for an explicit cast:
byte c = (byte) a + b; even though a and b are bytes.

Writing <byte c = (byte) a + b;> still gives you the same error!
It should rather states:
byte c = (byte) (a+b);
which works. If the aim was to work with byte values.
 
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