try catch...........

[faiza haris]

why does it give ... undeclared exception e.......error?

import java.io.*;
import java.net.*;
public class Base{
private void test(){
try{
String a= null;
String b= "b";
if(a==null)
throw new MalformedURLException("test");
if(b==null)
throw new EOFException("test");
}
catch(MalformedURLException e)
{System.out.println("caught malformed url");
throw e;}
catch(EOFException e)
{System.out.println("caught eof");
throw e;
}
finally {
System.out.println("end finally");
}

System.out.println("end processing");
}

public static void main(String args[]){
try {
new Base().test();
}
catch(Exception e)
{System.out.println("exceptn at main");}
}
}

I added some UBB code here. -Mapraputa
[This message has been edited by Mapraputa Is (edited October 19, 2000).]

[Surya Bahadur]

Hi
You need to say that your method throws exception if you are throwing that exception in your code,so change the method signature to
private void test() throws MalformedURLException,EOFException
Then your code would compile,or comment out the throw statement in the catch block.
Surya

[faiza haris]

thanx