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Math.round()

 
Varsha Dighe
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How come Math.round(9.5) = 10, but Math.round(-9.5) = -9, and yet Math.round(-9.6) = -10 ?
-Thanks
Varsha
 
P SOLAIAPPAN
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Math.round() will always roun up to nearest high value.
For e.g
Math.round(9.4)=9 // any value <9.5 will be rounded to 9<br /> Math.round(9.5)=10 // any value >=9.5 will be rounded to 10
Math.round(9.6)=10 //
Math.round(-9.5)= -9 // Note here -9.5 > -9.6 hence all the
numbers which are >=-9.5 will be
rounded to -9 which is a bigger number
than -10.

Math.round(-9.4)= -9 // -9.4>-9.5 hence -9
Math.round(-9.6)=-10 // since -9.6<-9.5<br /> Remember that -9 >-10
I hope u r clear

solaiappan
 
kamesh vadarevu
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Varsha,
Math.round() Rounds nearest int which is >0.5 ie if it is 9.0 to 9.5 you get 9.0 and if it is 9.6 to 9.9 you get 10.please remember sign is retained.Hope this helps.
kamesh
 
kamesh vadarevu
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OOPs I am wrong thank you soliappan.Varsha please check soliappan 's reply.
kamesh
 
Udayan Naik
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Hi Varsha.The general rule about rounding is :
round() will give the closest result to the argument passed to it. So from 0.0 to 0.4 it will give 0.0(nearest lower number) and from 0.5 to 1.0 it will give 1.0(nearest higher number).When u give a middle range argument(like 0.5) it will give the next higher number(like 1.0).
For negative numbers , -9 is greater than -9.5 thus u get round(-9.5) as -9 which is nearest higher number.
For -9.6 the nearest lower number is -10.0 thus round(-9.6) is -10.


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Varsha Dighe
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Thankyou very much to all for taking time to reply to my question. I think I understand it now
-Varsha
 
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