This week's book giveaway is in the Android forum. We're giving away four copies of Head First Android and have Dawn & David Griffiths on-line! See this thread for details.

Math.round() will always roun up to nearest high value. For e.g Math.round(9.4)=9 // any value <9.5 will be rounded to 9<br /> Math.round(9.5)=10 // any value >=9.5 will be rounded to 10 Math.round(9.6)=10 // Math.round(-9.5)= -9 // Note here -9.5 > -9.6 hence all the numbers which are >=-9.5 will be rounded to -9 which is a bigger number than -10.

Math.round(-9.4)= -9 // -9.4>-9.5 hence -9 Math.round(-9.6)=-10 // since -9.6<-9.5<br /> Remember that -9 >-10 I hope u r clear

Varsha, Math.round() Rounds nearest int which is >0.5 ie if it is 9.0 to 9.5 you get 9.0 and if it is 9.6 to 9.9 you get 10.please remember sign is retained.Hope this helps. kamesh

kamesh vadarevu
Greenhorn

Joined: Oct 17, 2000
Posts: 20

posted

0

OOPs I am wrong thank you soliappan.Varsha please check soliappan 's reply. kamesh

Hi Varsha.The general rule about rounding is : round() will give the closest result to the argument passed to it. So from 0.0 to 0.4 it will give 0.0(nearest lower number) and from 0.5 to 1.0 it will give 1.0(nearest higher number).When u give a middle range argument(like 0.5) it will give the next higher number(like 1.0). For negative numbers , -9 is greater than -9.5 thus u get round(-9.5) as -9 which is nearest higher number. For -9.6 the nearest lower number is -10.0 thus round(-9.6) is -10.

------------------ Come on in !! Drinks are on the house in the Big Moose Saloon !!

Udayan Naik<BR>Sun Certified Programmer for the Java 2 Platform

Varsha Dighe
Ranch Hand

Joined: Oct 14, 2000
Posts: 32

posted

0

Thankyou very much to all for taking time to reply to my question. I think I understand it now -Varsha