Accessibility

[Manish Singhal]

public class Tester {
public static void main(String[] args) {
System.out.println(new Sub().g());
}
private int f() {
return 2;
}
int g() {
return f();
}
}
class Sub extends Tester {
public int f() {
return 1;
}
}
I think output should be 1 but it is printing 2.
Methods can be overridden to be more public...then also ???
Please correct me !!!
Manish

[vijay krishna]

Cool!
In method int g() , it is return f() that is being called not Sub().return f()

[Manish Singhal]

Vijay I think there should be implicity "this".
Manish

[Bin Zhao]

Why go() method invokes f() in Tester class not the f() in Sub class?

[vijay krishna]

You are right manish. It has "this" , but see carefully this corresponds to one which is running! (i.e., Which has main method in it).

[midrisi]

It will print the value only 2
When you run the code it Sub().g() will be called as the inheritance suggest.But the g() will not having any access to f() function of Sub() as it is a function of parent class.So it will call f() function of Tester class itself.

I think your doubt has been cleared.
thanks

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[This message has been edited by midrisi (edited October 22, 2000).]

[Manish Singhal]

Thanks Midrisi. Doubt removed upto some extent.
Manish