can constructors throw exceptions

can any one explain this piece of code:
what is wrong with it??
the compiler says the exception must be caught,
but it's handled by the throws isn't it ??

public class Test {
int x = 0;

public Test(int inVal) throws Exception{
if (inVal != this.x){
throw new Exception("Invalid input");
}
}
public static void main(String args[]){
Test t = new Test(4);
}
}

thanx,
prasanthi

>the compiler says the exception must be caught,
>but it's handled by the throws isn't it ??
'throws' does not handle an exception, in fact, it makes the caller handle the exception!
>public Test(int inVal) throws Exception
This means: I'm going to throw an exception, you better handle it.

>Test t = new Test(4);
Now, here you should either catch the exception thrown by Test(4) or pass it on by declaring it in the throws clause of the main method.
Handling a Constructor that throws an exception is same as handling a method that throws an exception.
HTH,
Paul.

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I got your point.i didn't realize it.thanks
a lot paul.

thanks again.
prasanthi